16-8k^2=0

Solution for 16-8k^2=0 equation:

16-8k^2=0

a = -8; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-8)·16
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{2}}{2*-8}=\frac{0-16\sqrt{2}}{-16}
=-\frac{16\sqrt{2}}{-16}
=-\frac{\sqrt{2}}{-1}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{2}}{2*-8}=\frac{0+16\sqrt{2}}{-16}
=\frac{16\sqrt{2}}{-16}
=\frac{\sqrt{2}}{-1}
$